\(\dfrac{11}{10}+\dfrac{3}{5}:\dfrac{2}{3}\)
\(\dfrac{11}{10}+\dfrac{9}{10}\)
\(\dfrac{20}{10}=2\)
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Các câu hỏi tương tự
Bài 1:
a) 8/7 - 5/11 : 8 b) 1 + 2/9 : 7/3 - 10/7 c) 11/3 - 2 : 7/3 + 4
Bài 2:
a) 9/4 - x = 5/11 : 1/2 b) 2/9 : x = 7/3 - 10/7
Bài 3:
\(\dfrac{1999x1998-1}{1997x1999+1998}\)
Dien dau >,<,= :a)7/4-1/3...1/2-2/9.b)7/5-20/25...1/5+4/10. c)11/3-(2/5+3/5)...11/3-2/5-3/5
1/2+2/3+3/4+4/5+5/6+6/7+7/8+8/9+9/10+10/11+11/12+12/13+13/14+14/15=?
2/3-3/8:5/4=?
11/10 -2/5 :2/3=?
điền dấu lớn bé = vào chỗ chấm
9/8-5/6 .... 17/27-4/9
6-15/4....3/2+3/4
11/3-[5/3+2/3].....11/3-5/3-2/3
19/13+4/13-10/13....19/13-10/13+4/13
2/3 - 5/8 =
11/10 - 2/5 : 2/3 =
7/12 + 1/4 x 2/3 =
bài 1
4/7+4
3+6/11
3-5/7
21/9-2
15/24+2
63/45-20/25
3/4-2/8
6/7-5/8
37/45-5/9
46/39-11/13
5/12+3/4+1/3
1/2+3/7+11/14
7/10-(1/5+1/4)
15/4-2/3-3/4
5/6 + 7/12
9/16 - 3/8
11/10 + 3/5 : 2/3
\(\dfrac{2}{5}\) + \(\dfrac{5}{6}\)
\(\dfrac{11}{10}\) - \(\dfrac{2}{5}\) : \(\dfrac{2}{3}\)
\(\dfrac{2}{3}\) - \(\dfrac{3}{8}\)