\(\left(11-x\right)\left(4x-24\right)=0\\ \Rightarrow\left[{}\begin{matrix}11-x=0\\4x-24=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=11\\4x=24\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=11\\x=6\end{matrix}\right.\)
Vậy \(x\in\left\{11;6\right\}\)
11-x=0 hay 4x-24÷0
x=11 hay 4x=24
x=11 hay x=6
11-x=0 hay 4x-24÷0
x=11 hay 4x=24
x=11 hay x=6