=>1007-3x^2+27x+6x-54=0
=>-3x^2+33x+953=0
=>\(x=\dfrac{33\pm5\sqrt{501}}{6}\)
=>1007-3x^2+27x+6x-54=0
=>-3x^2+33x+953=0
=>\(x=\dfrac{33\pm5\sqrt{501}}{6}\)
1.Tìm số nguyên x thỏa mãn
(-2+x).(3x-6)=0
(3x+9).(2x+6)=0
1) (3x-6)(x+5)+4(x-2)=0
2) 3(x-5)(2x+9)+3x-15=0
3) (x2-16)(12-4x)=0
4) (9-x2)(4x-8)=0
5) (8-x3)(5x-125)=0
6) 4x=8
-x.(8-x)=0
(4-x).(x+3)=0
(3x-9).(2x-6)=0
(x-2).(2x-6)=0
(3x+9).(1-3x)=0
(x2+1).(81-x2) =0
5-|2x-1| = (-6)
|2-x| +2 =x
|x+1|=|x-3|
Tìm x, y biết
a,/2x/+/y-3/=0
b,/3x-6/+/3x-y+5/=0
c,34-2./9-3x/=0
Tim so nguyen x biet:
a,x-(-24)=3
b,(x+5)-(x-9)=x+3
c,c(x+2)=0
d,(x-1)^2=0
e,x^2-3x=0
f,-13-(6-|x+1|)=24
g,26-|x+9|=-13
i,(3x-6).3=3^4
tìm x,y thuộc Z:
a, -(3y+2)+(4y-5)=0
b,(3x-6)^2+ Iy-2I=0
c, (3x^2+9)x(x^2-4)x(25-x^2)>0
tìm số nguyên x biet
-2.(x+6)+6.(x-10)=8
x+5=20-(12-7)
(3x-9).(2x+6)=0
(2x+1).(3-x)=0
Tìm số nguyên x, biết
a) x – 2 = -6
b)15 – (x – 7) = -21
c)4.(3x – 4) – 2 = 18
d) (3x – 6) + 3 = 32
e) (3x – 6) . 3 = 32
f) (3x – 6) : 3 = 32
g) (3x – 6) - 3 = 32
h) (3x -2 mũ4 ).7mũ3 = 2.7mũ4
i) |x| = |-7| k) |x+1| = 2
l)|x – 2| = 3
m) x +|-2| = 0
o) 72 – 3.|x + 1| = 9
p) |x+1| = 3 và x+1< 0
q) (x – 2).(x + 4) = 0
1,x=3x2
2,(x+5)(x-3)-(x-30)=0
3,(2x-6)(x+4)+2(2x-6)=0
4,(2x-5)(x+9)+6x-15=0
3,(2x-5)(x+6)+8x-20=0