Question

1 Tính giá trị của biểu thức

\(\frac{\left(\frac{1}{2}\right)^2\cdot2018-\left(\frac{1}{4}\right)^6\cdot2017}{\frac{1}{4096}\cdot\frac{1}{3}+\left(\frac{1}{2}\right)^{13}}\)=

Answer 1

\(\frac{\left(\frac{1}{2}\right)^2.2018-\left(\frac{1}{4}\right)^2.2017}{\frac{1}{4096}.\frac{1}{3}+2^{13}}\)

=

Answer 2

\(\frac{\left(\frac{1}{2}\right)^2.2018-\left(\frac{1}{4}\right)^6.2017}{\frac{1}{4096}.\frac{1}{3}+2^{13}}\)\(\Leftrightarrow\frac{\left(\frac{1}{4}\right).2018-\left(\frac{1}{4096}\right).2017}{\frac{1}{4096}.\frac{1}{3}+2^{13}}\)

Lược bỏ các số giống nhau đi ta được :

\(\frac{\left(\frac{1}{4}\right).2018.2017}{\frac{1}{3}+2^{13}}\Leftrightarrow\frac{\left(\frac{1}{4}\right).2018.2017}{\frac{1}{3}.8192}\Leftrightarrow\frac{\frac{1}{4}.4070306}{\frac{8192}{3}}\)

\(=\frac{1017576,5}{\frac{8192}{3}}\)

Answer 3

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