Câu hỏi của 1234

Question

1) Tìm x biết

240-(x+5)=137

(2x-10)-20=110

Nguyễn Xuân Thành · Accepted Answer

$240-\left(x+5\right)=137$

$x+5=240-137$

$x+5=103$

$x=103-5=98$

b) $\left(2x-10\right)-20=110$

$2x-10=110+20$

$2x-10=130$

$2x=130+10$

$2x=140$

$x=140:2=70$Câu trả lời: $240-\left(x+5\right)=137$

$x+5=240-137$

$x+5=103$

$x=103-5=98$

b) $\left(2x-10\right)-20=110$

$2x-10=110+20$

$2x-10=130$

$2x=130+10$

$2x=140$

$x=140:2=70$

Hà Quang Minh · Answer

$a,240-\left(x+5\right)=137\
x+5=103\
x=98\
b,\left(2x-10\right)-20=110\
2x-10=130\
2x=140\
x=70$Câu trả lời: $a,240-\left(x+5\right)=137\
x+5=103\
x=98\
b,\left(2x-10\right)-20=110\
2x-10=130\
2x=140\
x=70$

Bùi Nguyễn Như Ngọc · Answer

a, 240-(x+5)=137
            x+5=240-137

x+5=103

x=   103-5=98

b,(2x-10)-20=110

2x-10=110+20

2x-10=130

2x=120

x=120:2

x=60       Câu trả lời: a, 240-(x+5)=137
            x+5=240-137