2Zn+O2-to>2ZnO
0,2---0,1------0,2
n Zn=\(\dfrac{13}{65}=0,2mol\)
=>mZnO=0,2.81=16,2g
=>m O2=0,1.32=3,2g
a: \(2Zn+O_2\rightarrow2ZnO\)
b: \(m_{ZnO}=\dfrac{13}{65}\cdot\left(65+16\right)=81\cdot0.2=16.2\left(g\right)\)
c: \(m_{O_2}=0.1\cdot16=1.6\left(g\right)\)