Ta có: \(1-\left(\frac{49}{9}+x-\frac{133}{18}\right):\frac{11}{2}=\frac{4}{9}\)
\(\Rightarrow\left(\frac{49}{9}+x-\frac{133}{18}\right):\frac{11}{2}=1-\frac{4}{9}=\frac{5}{9}\)
\(\frac{49}{8}+x-\frac{133}{19}=\frac{5}{9}.\frac{11}{2}=\frac{55}{18}\)
\(\frac{49}{8}+x=\frac{55}{18}+\frac{133}{19}=\frac{181}{18}\)
\(\Rightarrow x=\frac{181}{18}-\frac{49}{8}=\frac{283}{72}\)
Vậy \(x=\frac{283}{72}\)
1 - ( 49/9 + x -133/18 ):11/2 = 4/9
1 - ( 49/9 + x - 133/18 ) = 4/9 . 11/2
1 - ( 49/9 + x - 133/18 ) = 22/9
49/9 + x - 133/18 = 1 - 22/9
49/9 + x - 133/18 = - 13/9
49/9 + x = -13/9 - 133/18
49/9 + x = -53/6
x = -53/6 -49/9
x = -257/18
1 - (49/9 +x - 133/18) : 11/2 = 4/9
(49/9 + x - 133/18) :11/2 = 1- 4/9
(49/9 + x - 133/18) :11/2 = 5/9
49/9 + x - 133/18 = 5/9 * 11/2
49/9 + x - 133/18= 55/18
-35/18 + x = 55/18
x= 55/18 + 35/18
x= 5
