Question

1) √((3-√3)²)

2) √((3-2√2)²) + √((3+2√2)²)

Answer 1

\(1,=\left|3-\sqrt{3}\right|=3-\sqrt{3}\\ ---------\\ 2,=\left|3-2\sqrt{2}\right|+\left|3+2\sqrt{2}\right|=3-2\sqrt{2}+3+2\sqrt{2}=6\)

Answer 2

\(\sqrt{\left(3-\sqrt{3}\right)^2}=\left|3-\sqrt{3}\right|=3-\sqrt{3}\left(do:3>\sqrt{3}\right)\)

\(\sqrt{\left(3-2\sqrt{2}\right)^2}+\sqrt{\left(3+2\sqrt{2}\right)^2}\)

\(=\left|3-2\sqrt{2}\right|+\left|3+2\sqrt{2}\right|=3-2\sqrt{2}+3+2\sqrt{2}\)

`=6`