(1-2x)^2=9
(1-2x)^2=3^2 hoac=-3^2
Vay co 2 truong hop:
Truong hop 1 : 1-2x=3 Truong hop 2 : 1-2x=-3
2x=1-3 2x=1-(-3)
2x=-2 2x=4
x=-2:2=-1 x=4:2=2
: Tìm x, biết:
a) 3x( 4x- 1) - 2x(6x- 3 )=30 b) 2x(3-2x) + 2x(2x-1)=15
c) (5x-2)(4x-1) + (10x +3)(2x - 1)=1 d) (x+2) (x+2)- (x -3)(x+1) = 9
e) (4x+1)(6x-3) = 7 + (3x – 2)(8x + 9) g) (10x+2)(4x- 1)- (8x -3)(5x+2) =14
Bài 1: Tìm x biết \(\frac{5^{x+2}+5^{x+1}+5^x}{31}=\frac{9^{2x}+9^{2x+1}+9^{2\left(x+1\right)}}{91}\)
(2x-1)^9-(2x-1)^11=0
(2-3x)^13=(3x-2)^12
Tìm X biết: ( 9 x 2x - 1)^2 =(1-2x)^4
a) 5(x-2)(x+3)=1
b) 7(x-2024)2 = 23- y2
c) |x2+ 2x| + |y2- 9|= 0
d) 2x+ 2x+1+2x+2+2x+3=120
e) ( x- 7 )x+1- (x - 7)x+11=0
f) 25 - y2= 8(x 2012)2
Tìm x:
a) 3x.(1 - 2x) + 6x^2 - 7x = 8.(1 - 2x) - 9
b) 2x.(1 + 3x) - 3x.(4 +2x) = 3x - 4
Tìm x :
a) (2x+1)2=\(\dfrac{1}{9}\)
b)\(\sqrt{x+\dfrac{1}{2}}=\dfrac{1}{4}\)
c) \(\dfrac{x+1}{2x-1}=\dfrac{4}{5}\)
1)(3x+20)
2)2(-4x+9)
3)2x(x-45)
4)-5x(2x+47)
5)x^2-912
A; 5-|3x-1|=3
B; |x+3/4|-5=–2
C; (1 - 2x)^2 =9
D; (x+5)^3 =-64
E; (2x+1)^2=4/9
Ai giúp mình với ạ
Cho mình hỏi câu này với, hỏi toán lớp 7:
Tìm x biết:
a)(x-2)^2- (x-3)(x^2+3x+9) + 6(x+1)^2 = 9
b) (x+3)^3 - x(3x+1)^2(2x+1)(4x^2-2x+1)=28
