Question

1)(3x+20)
2)2(-4x+9)
3)2x(x-45)
4)-5x(2x+47)
5)x^2-912
 

Answer 1

`3x+20=0`

`=>3x=0-20`

`=>3x=-20`

`=>x=-20/3`

`---`

`2(-4x+9)=0`

`=>-4x+9=0`

`=>-4x=-9`

`=>x=9/4`

`---`

`2x(x-45)=0`

\(\Rightarrow\left[{}\begin{matrix}2x=0\\x-45=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=45\end{matrix}\right.\)

`---`

`-5x(2x+47)=0`

\(\Rightarrow\left[{}\begin{matrix}-5x=0\\2x+47=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=-\dfrac{47}{2}\end{matrix}\right.\)

`----`

`x^2 -912=0`

`=>x^2=912`

`=>x∈∅`

Answer 2

1)

`3x+20=0`

`<=>3x=-20`

`<=>x=-20/3`

 

2)

`2(-4x+9)=0`

<=>-4x+9=0`

`<=>-4x=-9`

`<=>x=9/4`

 

3)

`2x(x-45)=0`

\(< =>\left[{}\begin{matrix}2x=0\\x-45=0\end{matrix}\right.\\ < =>\left[{}\begin{matrix}x=0\\x=45\end{matrix}\right.\)

4)

`-x(2x+47)=0`

\(< =>\left[{}\begin{matrix}-x=0\\2x+47=0\end{matrix}\right.\\ < =>\left[{}\begin{matrix}x=0\\x=-\dfrac{47}{2}\end{matrix}\right.\)

5)

`x^2 -912=0`

`<=>x^2=912`

câu 5 xem lại nhé

Answer 3

tìm nghiệm của đa thức ạ