a: \(P=\left(\frac{2x}{3x+1}-1\right):\left(1-\frac{8x^2}{9x^2-1}\right)\)
\(=\frac{2x-3x-1}{3x+1}:\frac{9x^2-1-8x^2}{9x^2-1}\)
\(=\frac{-x-1}{3x+1}\cdot\frac{\left(3x-1\right)\left(3x+1\right)}{x^2-1}=\frac{-\left(x+1\right)\left(3x-1\right)}{\left(x-1\right)\left(x+1\right)}=\frac{-\left(3x-1\right)}{x-1}\)
b: Thay x=2 vào P, ta được:
\(P=\frac{-\left(3\cdot2-1\right)}{2-1}=-\frac51=-5\)

