Question

Answer 1

a: \(\frac{x+5}{2}+\frac{3-2x}{4}=x-\frac{x+7}{6}\)

=>\(\frac{6\left(x+5\right)}{12}+\frac{3\left(3-2x\right)}{12}=\frac{12x}{12}-\frac{2\left(x+7\right)}{12}\)

=>6(x+5)+3(3-2x)=12x-2(x+7)

=>12x-2x-14=6x+30+9-6x=39

=>10x=53

=>\(x=\frac{53}{10}\)

b: \(\frac{x+1}{35}+\frac{x+3}{33}=\frac{x+5}{31}+\frac{x+7}{29}\)

=>\(\left(\frac{x+1}{35}+1\right)+\left(\frac{x+3}{33}+1\right)=\left(\frac{x+5}{31}+1\right)+\left(\frac{x+7}{29}+1\right)\)

=>\(\frac{x+36}{35}+\frac{x+36}{33}=\frac{x+36}{31}+\frac{x+36}{29}\)

=>\(\left(x+36\right)\left(\frac{1}{29}+\frac{1}{31}-\frac{1}{33}-\frac{1}{35}\right)=0\)

=>x+36=0

=>x=-36