Ta có: \(\left|(\right|x-1\left|)\cdot\left(\left|2x-\frac34\right|\right)\right|=2x-\frac34\)
=>\(\begin{cases}2x-\frac34\ge0\\ \left(x-1\right)^2\cdot\left(2x-\frac34\right)^2=\left(2x-\frac34\right)^2\end{cases}\Rightarrow\begin{cases}x\ge\frac38\\ \left(2x-\frac34\right)^2\cdot\left\lbrack\left(x-1\right)^2-1\right\rbrack=0\end{cases}\)
=>\(\begin{cases}x\ge\frac38\\ \left(2x-\frac34\right)\left(x-1-1\right)\left(x-1+1\right)=0\end{cases}\Rightarrow\begin{cases}x\ge\frac38\\ \left(2x-\frac34\right)\cdot x\cdot\left(x-2\right)=0\end{cases}\)
=>\(x\in\left\lbrace\frac38;2\right\rbrace\)
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