a: Ta có: \(\left|x\right|=\frac{14}{15}\)
=>\(\left[\begin{array}{l}x=\frac{14}{15}\\ x=-\frac{14}{15}\end{array}\right.\)
b: ta có: |x+2,745|=0
=>x+2,745=0
=>x=-2,745
c: Ta có: \(\left|x-33\right|=-\sqrt5\)
mà \(-\sqrt5<0\)
nên x∈∅
d: Ta có: |x|=x
=>x>=0
e: |x|+|x+1|=0
=>\(\begin{cases}x=0\\ x+1=0\end{cases}\Rightarrow\begin{cases}x=0\\ x=-1\end{cases}\)
=>x∈∅
f: ta có: \(\left|\frac25+x\right|+\left|1,5-5x\right|=0\)
=>\(\begin{cases}x+\frac25=0\\ 1,5-5x=0\end{cases}\Rightarrow\begin{cases}x=-\frac25\\ 5x=1,5\end{cases}\Rightarrow\begin{cases}x=-\frac25\\ x=0,3=\frac{3}{10}\end{cases}\)
=>x∈∅
