Question

Answer 1

- CaO: 40 + 16 = 56 (g/mol)

- LiOH: 7 + 16 + 1 = 24 (g/mol)

- Na2SO4: 23 x 2 + 32 + 16 x 4 = 142 (g/mol)

- Cu(NO3)2 = 64 + 14 x 2 + 16 x 3 x 2 = 188 (g/mol)

- số mol \(Al_2O_3\) là: \(n=\dfrac{m}{M}=\dfrac{10,2}{102}=0,1\left(mol\right)\)

- số mol CO2 là: \(n=\dfrac{m}{M}=\dfrac{8,8}{44}=0,2\left(mol\right)\)

thể tích \(CO_2\) là: \(V=24,79\cdot n=24,79\cdot0,2=4,958\left(L\right)\)

- \(\dfrac{M_{H_2SO_4}}{M_{HNO_3}}=\dfrac{98}{63}=\dfrac{14}{9}\)