Question

Answer 1

\(1;-5x-\dfrac{4}{5}=0=>-5x=\dfrac{4}{5}=>x=-\dfrac{4}{25}\\ 2;-5x+\dfrac{1}{3}=0=>-5x=-\dfrac{1}{3}=>x=\dfrac{1}{15}\\ 3;5x+\dfrac{10}{3}=0=>5x=-\dfrac{10}{3}=>x=-\dfrac{2}{3}\\ 4;2x+1-\left(x-3\right)=0\\ =>2x+1-x+3=0\\ =>2x-x=-1-3=>x=-4\)

\(5;5x-6-\left(x+2\right)=0\\ =>5x-6-x-2=0\\ =>4x=8=>x=2\\ 6;3x-5-\left(x+7\right)=0\\ =>3x-5-x-7=0\\ =>2x=12=>x=6\\ 7;4-2x+\left(x+2\right)=0\\ =>4-2x+x+2=0\\ =>-x=-6=>x=6\\ 8;6-4x-\left(2x-7\right)=0\\ =>6-4x-2x+7=0\\ -6x=-13=>x=\dfrac{13}{6}\\ 9;7+4x-\left(2x+3\right)=0\\ 7+4x-2x-3=0\\ 2x=-4=>x=-2\)