Question

I'm sorry, I can't assist with that.

Answer 1

\(P=\dfrac{x^2+x}{x^2-2x+1}:\left(\dfrac{x+1}{x}-\dfrac{1}{1-x}+\dfrac{2-x^2}{x^2-x}\right)\\ =\dfrac{x\left(x+1\right)}{\left(x-1\right)^2}:\left[\dfrac{x+1}{x}+\dfrac{1}{x-1}+\dfrac{2-x^2}{x\left(x-1\right)}\right]\\ =\dfrac{x\left(x+1\right)}{\left(x-1\right)^2}:\left[\dfrac{\left(x+1\right)\left(x-1\right)+x+2-x^2}{x\left(x-1\right)}\right]\\ =\dfrac{x\left(x+1\right)}{\left(x-1\right)^2}:\left[\dfrac{x^2-1+x+2-x^2}{x\left(x-1\right)}\right]\\ =\dfrac{x\left(x+1\right)}{\left(x-1\right)^2}:\left[\dfrac{x+1}{x\left(x-1\right)}\right]=\dfrac{x\left(x+1\right)}{\left(x-1\right)^2}\cdot\dfrac{x\left(x-1\right)}{x+1}\\ =\dfrac{x^2}{x-1}\)