Ta có: x+y-2xy=4
=>x-2xy+y=4
=>\(x\left(1-2y\right)+y-0,5=4-0,5=3,5\)
=>\(-2x\left(y-0,5\right)+\left(y-0,5\right)=3,5\)
=>\(\left(-2x+1\right)\left(y-0,5\right)=3,5\)
=>\(\left(-2x+1\right)\left(2y-1\right)=7\)
=>(2x-1)(2y-1)=-7
=>(2x-1;2y-1)∈{(1;-7);(-7;1);(-1;7);(7;-1)}
=>(2x;2y)∈{(2;-6);(-6;2);(0;8);(8;0)}
=>(x;y)∈{(1;-3);(-3;1);(0;4);(4;0)}
