4x=5y
=>\(\frac{x}{5}=\frac{y}{4}\)
Đặt \(\frac{x}{5}=\frac{y}{4}=k\)
=>x=5k; y=4k
Ta có: \(x^2-y^2=1\)
=>\(\left(5k\right)^2-\left(4k\right)^2=1\)
=>\(25k^2-16k^2=1\)
=>\(9k^2=1\)
\(\Rightarrow k^2=\frac19\)
TH1: \(k=\frac13\)
=>\(x=5\cdot\frac13=\frac53;y=4\cdot\frac13=\frac43\)
TH2: \(k=-\frac13\)
=>\(x=5\cdot\frac{-1}{3}=-\frac53;y=4\cdot\frac{-1}{3}=-\frac43\)
