a: \(B=\left(3x-2\right)\left(9x^2+6x+4\right)\)
\(=\left(3x\right)^3-2^3=27x^3-8\)
Khi x=10/3 thì \(B=27\cdot\left(\dfrac{10}{3}\right)^3-8=10^3-8=1000-8=992\)
b: \(C=\left(2x-3y\right)\left(4x^2+6xy+9y^2\right)\)
\(=\left(2x\right)^3-\left(3y\right)^3\)
\(=8x^3-27y^3\)
Khi x=5;y=5/3 thì \(C=8\cdot5^3-27\cdot\left(\dfrac{5}{3}\right)^3=1000-27\cdot\dfrac{125}{27}=1000-125=875\)