1: Thay x=9 vào A, ta được:
\(A=\dfrac{9-4}{\sqrt{9}}=\dfrac{5}{3}\)
2: \(B=\dfrac{3}{\sqrt{x}-2}+\dfrac{2\sqrt{x}+3}{4-x}\)
\(=\dfrac{3}{\sqrt{x}-2}-\dfrac{2\sqrt{x}+3}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}\)
\(=\dfrac{3\left(\sqrt{x}+2\right)-2\sqrt{x}-3}{x-4}=\dfrac{3\sqrt{x}+6-2\sqrt{x}-3}{x-4}\)
\(=\dfrac{\sqrt{x}+3}{x-4}\)


