Question

Answer 1

\(\dfrac{\left(-2\right)^3\cdot\left(-2\right)^7}{4^6\cdot3}\)

\(=\dfrac{\left(-2\right)^{10}}{2^{12}\cdot3}=\dfrac{2^{10}}{2^{12}\cdot3}=\dfrac{1}{2^2\cdot3}=\dfrac{1}{4\cdot3}=\dfrac{1}{12}\)

Answer 2

`\frac{(-2)^3 \cdot (-2)^7}{4^6 \cdot 3} = -\frac{(-2)^{10}}{2^{12} \cdot 3} = -\frac{2^{10}}{2^{12} \cdot 3} = -\frac{1}{2^2 \cdot 3} = -\frac{1}{4 \cdot 3} = -\frac{1}{12}`

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