Bài 3:
\(1)x+\dfrac{1}{3}=-\dfrac{7}{3}\\ x=-\dfrac{7}{3}-\dfrac{1}{3}\\ x=-\dfrac{8}{3}\\ 2)\dfrac{1}{8}-x=\dfrac{3}{8}\\ x=\dfrac{1}{8}-\dfrac{3}{8}\\ x=-\dfrac{2}{8}\\ x=-\dfrac{1}{4}\\ 3)x-\dfrac{4}{5}=\dfrac{6}{5}\\ x=\dfrac{6}{5}+\dfrac{4}{5}\\ x=\dfrac{10}{5}\\ x=2\\ 4)\dfrac{2}{3}+x=\dfrac{7}{3}\\ x=\dfrac{7}{3}-\dfrac{2}{3}\\ x=\dfrac{5}{3}\\ 5)x-\dfrac{-7}{3}=\dfrac{5}{3}\\ x+\dfrac{7}{3}=\dfrac{5}{3}\\ x=\dfrac{5}{3}-\dfrac{7}{3}\\ x=-\dfrac{2}{3}\\ 6)x-\dfrac{1}{2}=\dfrac{9}{2}\\ x=\dfrac{9}{2}+\dfrac{1}{2}\\ x=\dfrac{10}{2}\\ x=5\\ 7)x+\dfrac{5}{4}=\dfrac{-3}{4}\\ x=-\dfrac{3}{4}-\dfrac{5}{4}\\ x=-\dfrac{8}{4}\\ x=-2\\ 8)x+\dfrac{2}{7}=\dfrac{5}{7}\\ x=\dfrac{5}{7}-\dfrac{2}{7}\\ x=\dfrac{3}{7}\\ 9)x-\dfrac{4}{3}=\dfrac{1}{3}\\ x=\dfrac{1}{3}+\dfrac{4}{3}\\ x=\dfrac{5}{3}\\ 10)x+\dfrac{5}{2}=\dfrac{-7}{2}\\ x=-\dfrac{7}{2}-\dfrac{5}{2}\\ x=-\dfrac{12}{2}\\ x=-6\)
