đk x^2 - 4x - 2 >= 0
\(16\left(2x-1\right)=\left(x^2-4x-2\right)^2\)
\(\Leftrightarrow32x-16=x^4-2x^2\left(4x+2\right)+\left(4x+2\right)^2\)
\(\Leftrightarrow x^4-8x^3-4x^2+16x^2+16x+4=32x-16\)
\(\Leftrightarrow x^4-8x^3+12x^2-16x+20=0\Leftrightarrow x=4+\sqrt{6}\left(tm\right);x=4-\sqrt{6}\left(l\right)\)