\(\dfrac{3x+2}{2}-\dfrac{3x+1}{6}=\dfrac{5}{3}+2x\)
=>\(\dfrac{3\left(3x+2\right)-3x-1}{6}=\dfrac{10+12x}{6}\)
=>\(3\left(3x+2\right)-3x-1=12x+10\)
=>9x+6-3x-1=12x+10
=>12x+10=6x+5
=>6x=-5
=>\(x=-\dfrac{5}{6}\)
\(\dfrac{3x+2}{2}-\dfrac{3x+1}{6}=\dfrac{5}{3}+2x\\ \Rightarrow\dfrac{\left(3x+2\right)\cdot3}{2\cdot3}-\dfrac{3x+1}{6}=\dfrac{5\cdot2}{3\cdot2}+\dfrac{\left(2x\right)\cdot6}{6}\\ \Rightarrow\dfrac{9x+6}{6}-\dfrac{3x+1}{6}=\dfrac{10}{6}+\dfrac{12x}{6}\\ \Rightarrow9x+6-3x-1=10+12x\\ \Rightarrow9x-3x-12x=10-6+1\\ \Rightarrow-6x=5\\ \Rightarrow x=\dfrac{5}{-6}=-\dfrac{5}{6}.\)
