Question

Answer 1

\(\left(3x^3y-\dfrac{1}{2}x^2+\dfrac{1}{5}xy\right).6xy^3\)

\(=18x^4y^4-3x^3y^3+\dfrac{6}{5}x^2y^4\)

Answer 2

\(\left(3x^3y-\dfrac{1}{2}x^2+\dfrac{1}{5}xy\right).6xy^3\)

\(=3x^3y.6xy^3-\dfrac{1}{2}x^2.6xy^3+\dfrac{1}{5}xy.6xy^3\)

\(=18x^4y^4-3x^3y^3+\dfrac{6}{5}x^2y^4\)