\(\left\{{}\begin{matrix}x-y=0\\x^2-2y+1=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=y\\x^2-2x+1=0\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}x=y\\\left(x-1\right)^2=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=y\\\left|x-1\right|=0\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}x=y\\x-1=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=y\\x=1\end{matrix}\right.\\ \Leftrightarrow x=y=1\)
Vậy: Hpt có cặp nghiệm (x;y)=(1;1)
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