Question

   

Answer 1

1: \(x-\dfrac{1}{2}=\dfrac{3}{4}\)

=>\(x=\dfrac{3}{4}+\dfrac{1}{2}=\dfrac{3}{4}+\dfrac{2}{4}=\dfrac{5}{4}\)

2: \(x+\dfrac{7}{8}=\dfrac{3}{4}\)

=>\(x=\dfrac{3}{4}-\dfrac{7}{8}=\dfrac{6}{8}-\dfrac{7}{8}=-\dfrac{1}{8}\)

3: \(\dfrac{1}{2}x-\dfrac{1}{4}=-\dfrac{1}{2}\)

=>\(\dfrac{1}{2}x=-\dfrac{1}{2}+\dfrac{1}{4}=\dfrac{-1}{4}\)

=>\(x=-\dfrac{1}{4}\cdot2=-\dfrac{1}{2}\)

4: \(\dfrac{-28}{35}=\dfrac{16}{x}\)

=>\(\dfrac{16}{x}=-\dfrac{4}{5}\)

=>\(x=\dfrac{-16\cdot5}{4}=-20\)

5: \(\dfrac{-2}{3}=\dfrac{x}{-9}\)

=>\(\dfrac{x}{9}=\dfrac{2}{3}\)

=>\(x=9\cdot\dfrac{2}{3}=6\)

6: \(\dfrac{-7}{8}=\dfrac{14}{x}\)

=>\(x=\dfrac{14\cdot8}{-7}=-2\cdot8=-16\)

7: \(\dfrac{x}{3}=\dfrac{2}{3}+\dfrac{-1}{7}\)

=>\(\dfrac{x}{3}=\dfrac{14-3}{21}\)

=>\(\dfrac{x}{3}=\dfrac{11}{21}\)
=>\(x=\dfrac{11}{21}\cdot3=\dfrac{11}{7}\)