Question

Answer 1

a: \(x+\dfrac{11}{12}=\dfrac{23}{24}\)

=>\(x=\dfrac{23}{24}-\dfrac{11}{12}=\dfrac{23}{24}-\dfrac{22}{24}=\dfrac{1}{24}\)

b: \(\dfrac{11}{8}-\dfrac{3}{8}\cdot x=\dfrac{1}{8}\)

=>\(x\cdot\dfrac{3}{8}=\dfrac{11}{8}-\dfrac{1}{8}=\dfrac{10}{8}\)

=>\(x=\dfrac{10}{8}:\dfrac{3}{8}=\dfrac{10}{3}\)

c: x:(-0,5)=-1,2

=>\(x=-1,2\cdot\left(-0,5\right)=0,6\)

d: \(\left(x-\dfrac{1}{2}\right)^2=\dfrac{1}{4}\)

=>\(\left[{}\begin{matrix}x-\dfrac{1}{2}=\dfrac{1}{2}\\x-\dfrac{1}{2}=-\dfrac{1}{2}\end{matrix}\right.\)

=>\(\left[{}\begin{matrix}x=1\\x=0\end{matrix}\right.\)