Question

Answer 1

1: \(\dfrac{0,5x^5+3,2x^3-2x^2}{0,25x^2}\)

\(=\dfrac{0.5x^5}{0.25x^2}+\dfrac{3.2x^3}{0.25x^2}-\dfrac{2x^2}{0,25x^2}\)

\(=2x^3+12,8x-8\)

2: \(\dfrac{A}{B}=\dfrac{x^3+2x^2-2x+2}{x-1}\)

\(=\dfrac{x^3-x^2+3x^2-3x+x-1+3}{x-1}\)

\(=x^2+3x+1+\dfrac{3}{x-1}\)

=>Phần dư là 3

3:

\(\dfrac{2x^4-3x^3+3x-2}{x^2-1}\)

\(=\dfrac{2x^4-2x^2-3x^3+3x+2x^2-2}{x^2-1}\)

\(=\dfrac{2x^2\left(x^2-1\right)-3x\left(x^2-1\right)+2\left(x^2-1\right)}{x^2-1}\)

\(=2x^2-3x+2\)

=>Dư là 0