Question

Answer 1

\(2008A=\dfrac{2008^{2009}+2008}{2008^{2009}+1}=1+\dfrac{2007}{2008^{2009}+1}\)

\(2008B=\dfrac{2008^{2008}+2008}{2008^{2008}+1}=1+\dfrac{2007}{2008^{2008}+1}\)

Ta có: \(2008^{2009}+1>2008^{2008}+1\)

=>\(\dfrac{2007}{2008^{2009}+1}< \dfrac{2007}{2008^{2008}+1}\)

=>\(\dfrac{2007}{2008^{2009}+1}+1< \dfrac{2007}{2008^{2008}+1}+1\)

=>2028A<2028B

=>A<B

Answer 2

mọi người giúp mình câu này với, cảm ơn mọi người