a: ĐKXĐ: \(x\notin\left\{-2;2;0\right\}\)
b: \(E=\left(\dfrac{1}{x+2}+\dfrac{1}{x-2}\right)\cdot\dfrac{x^2+4x+4}{2x}\)
\(=\dfrac{x-2+x+2}{\left(x+2\right)\left(x-2\right)}\cdot\dfrac{\left(x+2\right)^2}{2x}\)
\(=\dfrac{2x\left(x+2\right)}{2x\left(x-2\right)}=\dfrac{x+2}{x-2}\)
c: Thay x=1 vào E, ta được:
\(E=\dfrac{1+2}{1-2}=\dfrac{3}{-1}=-3\)