a: \(-\dfrac{2}{5}+\dfrac{4}{5}x=\dfrac{3}{5}\)
=>\(\dfrac{4}{5}x=\dfrac{3}{5}+\dfrac{2}{5}\)
=>\(\dfrac{4}{5}x=\dfrac{5}{5}=1\)
=>\(x=1:\dfrac{4}{5}=\dfrac{5}{4}\)
b: \(-\dfrac{3}{7}-\dfrac{4}{7}:x=-2\)
=>\(\dfrac{4}{7}:x+\dfrac{3}{7}=2\)
=>\(\dfrac{4}{7}:x=2-\dfrac{3}{7}=\dfrac{11}{7}\)
=>\(x=\dfrac{4}{7}:\dfrac{11}{7}=\dfrac{4}{11}\)
c: \(x-\dfrac{10}{3}=\dfrac{7}{15}\cdot\dfrac{3}{5}\)
=>\(x-\dfrac{10}{3}=\dfrac{21}{75}=\dfrac{7}{25}\)
=>\(x=\dfrac{7}{25}+\dfrac{10}{3}=\dfrac{21+250}{75}=\dfrac{251}{75}\)
d: \(x+\dfrac{3}{22}=\dfrac{27}{121}\cdot\dfrac{11}{9}\)
=>\(x+\dfrac{3}{22}=\dfrac{27}{9}\cdot\dfrac{11}{121}=\dfrac{3}{11}\)
=>\(x=\dfrac{3}{11}-\dfrac{3}{22}=\dfrac{3}{22}\)
e: \(\dfrac{8}{23}\cdot\dfrac{46}{24}-x=\dfrac{1}{3}\)
=>\(\dfrac{8}{24}\cdot\dfrac{46}{23}-x=\dfrac{1}{3}\)
=>\(\dfrac{2}{3}-x=\dfrac{1}{3}\)
=>\(x=\dfrac{1}{3}\)
f: \(1-x=\dfrac{49}{65}\cdot\dfrac{5}{7}\)
=>\(1-x=\dfrac{49}{7}\cdot\dfrac{5}{65}=\dfrac{7}{13}\)
=>\(x=1-\dfrac{7}{13}=\dfrac{6}{13}\)
g: \(\dfrac{62}{7}\cdot x=\dfrac{29}{9}:\dfrac{3}{56}\)
=>\(\dfrac{62}{7}\cdot x=\dfrac{29}{9}\cdot\dfrac{56}{3}=\dfrac{1624}{27}\)
=>\(x=\dfrac{1624}{27}:\dfrac{62}{7}=\dfrac{5684}{837}\)
h: \(\dfrac{1}{5}:x=\dfrac{1}{5}+\dfrac{1}{7}\)
=>\(\dfrac{1}{5}:x=\dfrac{12}{35}\)
=>\(x=\dfrac{1}{5}:\dfrac{12}{35}=\dfrac{1}{5}\cdot\dfrac{35}{12}=\dfrac{7}{12}\)
i: \(\dfrac{1}{2\cdot3^2+1}:x=2\)
=>\(\dfrac{1}{2\cdot9+1}:x=2\)
=>\(\dfrac{1}{19}:x=2\)
=>\(x=\dfrac{1}{19}:2=\dfrac{1}{38}\)
