Bài 1:
a: \(1\dfrac{3}{4}-0,25=\dfrac{7}{4}-\dfrac{1}{4}=\dfrac{6}{4}=\dfrac{3}{2}\)
b: \(15\dfrac{2}{3}:\left(-\dfrac{1}{3}\right)+\sqrt{25}=\dfrac{47}{3}\cdot\dfrac{3}{-1}+5=-47+5=-42\)
Bài 2:
a: \(4:15=x:3\)
=>\(\dfrac{x}{3}=\dfrac{4}{15}\)
=>\(x=\dfrac{4}{15}\cdot3=\dfrac{12}{15}=\dfrac{4}{5}\)
b: \(\dfrac{1}{3}-3x=\left(-\dfrac{2}{3}\right)^2\)
=>\(\dfrac{1}{3}-3x=\dfrac{4}{9}\)
=>\(3x=\dfrac{1}{3}-\dfrac{4}{9}=-\dfrac{1}{9}\)
=>\(x=-\dfrac{1}{9}:3=-\dfrac{1}{27}\)
