ĐKXĐ: x>=0
\(\left(0,5-2x\right)\left(\sqrt{x}-2\right)=0\)
=>\(\left[{}\begin{matrix}0,5-2x=0\\\sqrt{x}-2=0\end{matrix}\right.\)
=>\(\left[{}\begin{matrix}2x=0,5\\\sqrt{x}=2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0,25\left(nhận\right)\\x=4\left(nhận\right)\end{matrix}\right.\)