a: ΔABC=ΔMNP
=>\(\widehat{A}=\widehat{M};\widehat{B}=\widehat{N};\widehat{C}=\widehat{P}\)
b: \(\widehat{A}=\widehat{M}=65^0\)
\(\widehat{C}=\widehat{P}=30^0\)
Xét ΔABC có \(\widehat{A}+\widehat{C}+\widehat{B}=180^0\)
=>\(\widehat{B}=180^0-65^0-30^0=85^0\)
=>\(\widehat{N}=85^0\)
ΔABC=ΔMNP
=>AB=MN=10cm; BC=NP=12cm
