Question

Answer 1

a: \(\dfrac{x-5}{3}=\dfrac{2x-1}{4}\)

=>\(3\left(2x-1\right)=4\left(x-5\right)\)

=>\(6x-3=4x-20\)

=>\(6x-4x=-20+3\)

=>2x=-17

=>\(x=-\dfrac{17}{2}\)

b: ĐKXĐ: \(x\notin\left\{2;1\right\}\)

\(\dfrac{x+3}{x-2}=\dfrac{x-2}{x-1}\)

=>\(\left(x+3\right)\left(x-1\right)=\left(x-2\right)\left(x-2\right)\)

=>\(x^2-x+3x-3=x^2-4x+4\)

=>2x-3=-4x+4

=>6x=7

=>\(x=\dfrac{7}{6}\left(nhận\right)\)