Question

Answer 1

Theo hình thì ta có OD//AB

=>\(\widehat{AOD}=\widehat{OAB}\)(hai góc so le trong)

=>\(\widehat{AOD}=120^0\)

\(\widehat{AOD}+\widehat{DOE}=180^0\)(hai góc kề bù)

=>\(y+120=180^0\)

=>\(y=60^0\)

\(\widehat{COE}=\widehat{COD}+\widehat{DOE}\)

\(=45^0+60^0=105^0\)

\(\widehat{COE}=\widehat{AOG}\)

=>\(x=\widehat{COE}=105^0\)