\(B=\dfrac{x+27}{x-9}+\dfrac{1}{\sqrt{x}+3}+\dfrac{6}{3-\sqrt{x}}\\ =\dfrac{x+27}{\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)}+\dfrac{1}{\sqrt{x}+3}-\dfrac{6}{\sqrt{x}-3}\\ =\dfrac{x+27+\sqrt{x}-3-\sqrt{x}-3}{\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)}\\ =\dfrac{x-21}{x-9}\)

