Đặt x-2014=a; x+2012=b
Theo đề, ta có: a^3+b^3=(a+b)^3
=>\(a^3+b^3+3ab\left(a+b\right)-a^3-b^3=0\)
=>\(3ab\left(a+b\right)=0\)
=>\(ab\left(a+b\right)=0\)
=>\(\left(x-2014\right)\left(x+2012\right)\left(2x-2\right)=0\)
=>\(x\in\left\{2014;-2012;1\right\}\)


