\(\left(\dfrac{-3}{5}\right)\cdot x=\left(\dfrac{-3}{5}\right)^5\)
\(\Rightarrow x=\left(\dfrac{-3}{5}\right)^5:\left(\dfrac{-3}{5}\right)\)
\(\Rightarrow x=\left(\dfrac{-3}{5}\right)^4\)
\(\Rightarrow x=\dfrac{81}{625}\)
Vậy: \(x=\dfrac{81}{625}\)
#\(Toru\)
