Question

Answer 1

1)

`(x+3)^3=x^3+3*x^2*3+3*x*3^2+3^3=x^3+9x^2+27x+27`

2)

`(1+x)^3=1^3+3*1^2*x+3*1*x^2+x^3=1+3x+3x^2+x^3`

3)

`(2-x)^3=2^3-3*2^2*x+3*2*x^2-x^3=8-12x+6x^2-x^3`

4)

`(x-3)^3=x^3-3*x^2*3+3*x*3^2-3^3=x^3-9x^2+27x-27`

Answer 2

1) \(\left(x+3\right)^3=x^3+3.3^2.x+3.3.x^2+3^3=x^3+9x^2+27x+27\)

2) \(\left(1+x\right)^3=1^3+3.1^2.x+3.1.x^2+x^3=x^3+3x^2+3x+1\)

3) \(\left(2-x\right)^3=2^3-3.2^2.x+3.2.x^2-x^3=-x^3+6x^2-12x+8\)

4) \(\left(x-3\right)^3=x^3-3.x^2.3+3.x.3^3-3^3=x^3-9x^2+81x-27\)