Question

  

Answer 1

a, \(H_2+CuO\underrightarrow{t^o}Cu+H_2O\)

b, \(n_{Cu}=\dfrac{0,32}{64}=0,005\left(mol\right)\)

\(n_{CuO}=n_{Cu}=0,005\left(mol\right)\Rightarrow m_{CuO}=0,005.80=0,4\left(g\right)\)

c, \(n_{H_2}=n_{Cu}=0,005\left(mol\right)\Rightarrow V_{H_2}=0,005.24,79=0,12395\left(l\right)\)

d, \(n_{H_2O}=n_{Cu}=0,005\left(mol\right)\Rightarrow m_{H_2O}=0,005.18=0,09\left(g\right)\)