Ta có: \(m_{Fe}=1000.96\%=960\left(kg\right)\Rightarrow n_{Fe}=\dfrac{960}{56}=\dfrac{120}{7}\left(kmol\right)\)
BTNT Fe, có: \(n_{Fe_2O_3\left(LT\right)}=\dfrac{1}{2}n_{Fe}=\dfrac{60}{7}\left(kmol\right)\)
Mà: H = 80%
\(\Rightarrow n_{Fe_2o_3\left(TT\right)}=\dfrac{\dfrac{60}{7}}{80\%}=\dfrac{75}{7}\left(kmol\right)\)
\(\Rightarrow m_{Fe_2O_3\left(TT\right)}=\dfrac{75}{7}.160=\dfrac{12000}{7}\left(kg\right)\)
\(\Rightarrow m_{hematit}=\dfrac{\dfrac{12000}{7}}{60\%}=\dfrac{20000}{7}\left(kg\right)\)
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