25 tháng 9 2023 lúc 11:58
\(\dfrac{x+2020}{2}+\dfrac{2x+4040}{7}=\dfrac{x+2020}{5}+\dfrac{x+2020}{6}\)
\(\Rightarrow\dfrac{x+2020}{2}+\dfrac{2x+4040}{7}-\dfrac{x+2020}{5}-\dfrac{x+2020}{6}=0\)
\(\Rightarrow\dfrac{x+2020}{2}+\dfrac{2\left(x+2020\right)}{7}-\dfrac{x+2020}{5}-\dfrac{x+2020}{6}=0\)
\(\Rightarrow\left(x+2020\right)\cdot\left(\dfrac{1}{2}+\dfrac{2}{7}-\dfrac{1}{5}-\dfrac{1}{6}\right)=0\)
Mà: \(\dfrac{1}{2}+\dfrac{2}{7}-\dfrac{1}{5}-\dfrac{1}{6}\ne0\)
\(\Rightarrow x+2020=0\)
\(\Rightarrow x=-2020\)
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