Question

Answer 1

1:

a: \(\dfrac{5}{xy}=\dfrac{5y^2}{xy^3};\dfrac{1}{xy^3}=\dfrac{1}{xy^3}\)

b: \(\dfrac{1}{x^2+x}=\dfrac{1}{x\left(x+1\right)};\dfrac{2}{x}=\dfrac{2\left(x+1\right)}{x\left(x+1\right)}\)

c: \(\dfrac{x^2-4}{x^2+2x}=\dfrac{x^2-4}{x\left(x+2\right)};\dfrac{x}{x+2}=\dfrac{x^2}{x\left(x+2\right)}\)

d: \(\dfrac{2}{x^2-5x+6}=\dfrac{2}{\left(x-3\right)\left(x-2\right)};\dfrac{3}{x-2}=\dfrac{3\left(x-3\right)}{\left(x-2\right)\left(x-3\right)}\)

Answer 2

mn giúp e vs ạ e đg gấp e cảm ơn ạ