Question

Answer 1

Bài II:

a)

\(ĐK:x\le\dfrac{1}{3}\)

PT trở thành:

\(1-3x=4^2=16\\ \Leftrightarrow3x=1-16=-15\\ \Leftrightarrow x=-\dfrac{15}{3}=-5\left(tm\right)\)

Vậy `x=-5`

b)

\(ĐK:x\ge-2\)

PT trở thành:

\(\sqrt{x+2}+\sqrt{9}.\sqrt{x+2}-\sqrt{4}\sqrt{x+2}-6=0\\ \Leftrightarrow\sqrt{x+2}+3\sqrt{x+2}-2\sqrt{x+2}-6=0\\ \Leftrightarrow2\sqrt{x+2}=6\\ \Leftrightarrow\sqrt{x+2}=3\\ \Leftrightarrow x+2=3^2=9\\ \Leftrightarrow x=7\left(tm\right)\)

Vậy `x=7`

`HaNa♬D`