c) \(\left(x+3\right)\left(-8x\right)+4x\left(2x+7\right)=3x-10\)
\(\Leftrightarrow-8x^2-24x+8x^2+28x=3x-10\)
\(\Leftrightarrow\left(-8x^2+8x^2\right)+\left(-24x+28x\right)=3x-10\)
\(\Leftrightarrow4x=3x-10\)
\(\Leftrightarrow4x-3x=-10\)
\(\Leftrightarrow x=-10\)
Vậy: x= -10
