\(e,\left(3+2x\right)^2=\dfrac{1}{4}\\ \Leftrightarrow\left[{}\begin{matrix}2x+3=\dfrac{1}{2}\\2x+3=-\dfrac{1}{2}\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}2x=-\dfrac{5}{2}\\2x=-\dfrac{7}{2}\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{5}{4}\\x=-\dfrac{7}{2}\end{matrix}\right.\)
\(f,\left(5x-1\right)^3=-\dfrac{1}{27}\\ \Leftrightarrow5x-1=-\dfrac{1}{3}\\ \Leftrightarrow5x=\dfrac{2}{3}\\ \Leftrightarrow x=\dfrac{2}{15}\)
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