Question

Answer 1

1: =>(2x-1)^3=0

=>2x-1=0

=>x=1/2

2: =>(x-2)^3=27

=>(x-2)^3=3^3

=>x-2=3

=>x=5

3: =>(x-4)^2=-5(x-4)^3

=>5(x-4)^3+(x-4)^2=0

=>(x-4)^2*[5(x-4)+1]=0

=>(x-4)^2*(5x-19)=0

=>x=4;x=19/5

4: \(\left(2-x\right)^3=6x\left(x-2\right)\)

=>\(\left(x-2\right)^3+6x\left(x-2\right)=0\)

=>x^3-8=0

=>x^3=8

=>x=2

5: =>\(x^3+3x^2+3x+1-x^3+3x^2-3x+1-6\left(x^2-2x+1\right)=-10\)

=>\(6x^2+2-6x^2+12x-6=-10\)

=>12x-4=-10

=>12x=-6

=>x=-1/2